Converting C code to BrightScript question

Archived
1

I have some libraries that I want to translate from C and I have a question. What would be the best way to convert a function that has pointer as argument? Something like this:

void someFunction(int *num1, int *num2)
{
   *num1 = *num1 + 1;
   *num2 = *num2 + 2;
}

Here is what I came up with, but I wonder if there is a better solution:

function someFunction(num1, num2)
  return {
    num1: num1 + 1
    num2: num2 + 2 
   }
end function

and then call it in code something like this:

num1 = 1
num2 = 2
a = someFunction(num1, num2)
num1 = a.num1
num2 = a.num2

Any better way to do this?

2

If you use the roInt object type and the ifInt interface you can modify the num1 and num2 in place:

Sub someSub(num1 as Object, num2 as Object)
    num1.setInt(num1 + 1)
    num2.setInt(num2 + 2)
End Sub

To use it:

num1 = CreateObject("roInt")
num2 = CreateObject("roInt")
num1.setInt(1)
num2.setInt(2)
someSub(num1,num2)
print num1,num2

Produces:

2         4

I’m not saying this is really a better way to do it since the first time you forget to use the setInt interface (e.g., num1 += 1 or just initializing it without setInt) you turn it into an Integer and it’s no longer an roInt object and someSub will no longer modify it in place.

-JT

3

“renojim” wrote:
If you use the roInt object type and the ifInt interface you can modify the num1 and num2 in place:

Sub someSub(num1 as Object, num2 as Object)
    num1.setInt(num1 + 1)
    num2.setInt(num2 + 2)
End Sub

To use it:

num1 = CreateObject("roInt")
num2 = CreateObject("roInt")
num1.setInt(1)
num2.setInt(2)
someSub(num1,num2)
print num1,num2

Produces:

2         4

I’m not saying this is really a better way to do it since the first time you forget to use the setInt interface (e.g., num1 += 1 or just initializing it without setInt) you turn it into an Integer and it’s no longer an roInt object and someSub will no longer modify it in place.

-JT
Thank you! This is very good to know.