correct way to get the node name

Archived
1

how is one meant to access this? I get a crash when I do m.top.name

2

The “id” of the node, usually set first in the XML, is available at m.top.id.

If you mean the “type”, such as RowList, ButtonGroup, use m.top.subtype()

3

Thanks, I should’ve updated this question as I’d already worked this out :slightly_smiling_face:

Thanks for responding though.