Markup Grid get focussed Child

Archived
1

Hi,

I have a MarkupGrip and am observing the itemFocused field. However, I’m struggling to get the focused child Node then this event is fire.

In the below code I can get the focused index and content, but what a I really what is the SG Node so I can find out it’s screen position.

Sorry if this is a newbie question.

sub onItemFocused()
    focused = m.grid.itemFocused
    content = m.grid.content.getChild(focused)
    ' but how to get the Node for the focused item. I'd like this so I can find out it's position on screen
end sub

Thanks,

Ryan

2

You should be able to use one of the subBoundingRect methods to find the position of the focused item.

3

Thanks, subBoundingRect does work. But the odd thing is, the string passed as the item number seems to be ignored.

For a 30 item grid the following always produces the same result:


grid.subBoundingRect("item1")
grid.subBoundingRect("item20")

The Rect returned is always the rect of the focused cell and not the rect of the item in the grid. Is that by design?

Thanks,

Ryan