objects and functions question

Archived
1

Hi,

I have a function like this:

bigfunc=init()

function init() as object
   return {label:functionname,lable1:function1name,lable2:function2name} 
end function

(really, a huge pile of functions in one object)

I have an array of items which each have an action with the same name as the lable in bigfunc:


item[1].action="lable1"
item[1].id="23423452"
item[2].action="lable2"
item[2].id="23256562"

what I want to do is to use the value stored in item

2

“jbrave” wrote:

this=“function1name”
this(id)

but I get:

Member function not found in BrightScript Component or interface.

I can explicitly call bigfunc.lable1(id)

and the function executes.

is there a way to do this without using exec()

  • Joel

That’s PHP style, which is sort of it’s own unique PHP thing (go figure).

I’m not sure, but if it’s a regular function, you may have to use eval(). If it’s actually a method on an object, you are in luck. Gander at this:


function func1()
    print m.v1
end function

manualObj = {
    v1: 1
    f1: func1
    f2: func2
}

print manualObj.v1 ' prints "1"
print manualObj["v1"] ' also prints "1"
varname = "v1"
print manualObj[varname] ' prints "1" yet again

manualObj.f1() ' prints "1"
manualObj["f1"]() ' also prints "1"
funcname = "f1"
manualObj[funcname]() ' prints "1" yet again

The thing to remember is that a variable can contain a function, just as it can contain a value. In this case, a function is just a special type, like an int or string. In a language this is called “first class functions” (http://en.wikipedia.org/wiki/First-class_function). It’s different than PHP, much more powerful and actually more common. The way[ to determine whether you are calling the function or accessing it’s code/contents is whether you append the parenthesis (manualObj.f1 vs manualObj.f1() above).

3 
funcname = "f1"
manualObj[funcname]() ' prints "1" yet again

This looks like what I’m looking for,

Thanks!

-Joel