video player format question

Archived
1

What is the minimal amount of data I need to send to the video player to get it to play?

I’ve got an mp4 video, h.264 (according to Quicktime) but when I try to play it I’m getting

showVideoScreen | msg = The format is not supported or the media is corrupt. | index = -5
request failed error: -5 The format is not supported or the media is corrupt.

I threw the vid player together from an example in the Object reference. Here’s the tiny bit of data I send to it:

port = CreateObject(“roMessagePort”)
screen = CreateObject(“roVideoScreen”)
episode.HDBranded = false
episode.IsHD = false

episode.Stream = { url:playurl
quality:false
}

episode.StreamFormat=“mp4”

screen.SetContent(episode)
screen.SetMessagePort(port)
screen.Show()

2

All you absolutely have to provide is the URL. Roku assumes mp4 if you omit the format. As an example, this works fine…

Sub Main()
  vid = {
    stream:	{
    	url:	"http://msnbcpod.rd.llnwd.net/e1/video/podcast/pdv_countdown_netcast_m4v-10-25-2010-195641.m4v"
    }
  }
  
  screen = CreateObject("roVideoScreen")
  screen.SetMessagePort(CreateObject("roMessagePort"))
  screen.SetContent(vid)
  screen.Show()

  while true
    msg = wait(0, screen.GetMessagePort())

    if msg <> invalid then
      if msg.isScreenClosed()
        exit while
      end if
    end if
  end while
end sub
3

as it turns out, that was exactly what I did wrong: I use “playurl” as the variable name but used “url” when I called the play sub!